How to Prevent Web Form SPAM - Solved PHP

Very simple after getting spammed 47000 times in 8 days, i found this solutions.

Dont go with Preg or rpreg etc etc

Just put common keywords in an array & boot the mother fuckers with EXIT(0) when they caught redhanded spamming on your website.

no mother fucker can now, spam on my holy-FORM

$owned_urls = array('blog','http','medicine','10 mg','article','product','porn','bitch','http','25 mg','0.25 mg',' mg','purchase','clinical','diseases','pain','oxy','children','kids'); $string = strtolower('i have a medicine for your to look into'); //$owned_urls = array('website1.com', 'website2.com', 'website3.com'); /// $string = 'my domain name is website3.com'; for($i=0; $i < count($owned_urls); $i++) { if(strpos($string,$owned_urls[$i]) != false){ echo 'Found'; } else { exit(0); echo 'stop it'; } }

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Website Form Live Data Feed to Mobile APPs Service

How to Submit Website Form Data to Mobile / Smartphone APPS Live Data Feed?

This is very intresting topic that every developer loosing hair on...

Lets Say your client has a website with A Form. That Form Can Be :

• Reservation Form (Taxi / Limo / Truck / Cargo / Shipping / Doctor Appointment etc)
• Client Enquiry Form
• Advance Reservation
• Support Service

Et Cetera, Et Cetera ...

What Clients Want?

---> Wants Website Form Submission Real Time Data to be Relayed on His Mobile / SmartPhone Apps

---> Feed Website Form Submission Data to Smartphone Apps

We provide Real Time Data Relay from Your Website Forms to SmartPhone Apps

Quick Tip: Making a Fancy WordPress Register Form from Scratch

Quick Tip: Making a Fancy WordPress Register Form from Scratch

In this tutorial, I will guide you through the process of making a beautiful “Register” form, using Fancybox, jQuery, and, of course, WordPress. As you’ll find, the process is really quite simple.

PHP file from an onsubmit

You cannot call a PHP file from an onsubmit, only javascript files.
What you can do:
echo "

";
echo "

When you submt, it will load the page again, do a check at the top of the page:
if (isset($_POST["sendchekc"] && $_POST["sendcheck"] == "ok")
{
$delme = mysql_query("update preorder set deleted='1' where preord_prodno='" . $_POST["preprodno"] . "'",$con) or die('Sorry Dear! product could not be deleted : ' . mysql_error());
}

If you don't want the page to reload, look for an AJAX method ...