MySQL & PHP References: Extract Geocoding Latitude Longitude from Image / Photo using PHP with Google MAP API [SOLVED]

Sunday, April 19, 2020

Extract Geocoding Latitude Longitude from Image / Photo using PHP with Google MAP API [SOLVED]

Extract Latittude and Longitude from an photo shot using GPS Enabled device either Smartphone or Digital Camera using PHP & show the location on Google MAP with Marker.

I tried using EXIF.JS & jQuery but failed. PHP is simple and works great.

<!DOCTYPE html>
<html>
<head>
  <title></title>
</head>
<body>

<?php 
function gps2Num($coordPart){
    $parts = explode('/', $coordPart);
    if(count($parts) <= 0)
    return 0;
    if(count($parts) == 1)
    return $parts[0];
    return floatval($parts[0]) / floatval($parts[1]);
}

function get_image_location($image = ''){
    $exif = exif_read_data($image, 0, true);
    if($exif && isset($exif['GPS'])){
        $GPSLatitudeRef = $exif['GPS']['GPSLatitudeRef'];
        $GPSLatitude    = $exif['GPS']['GPSLatitude'];
        $GPSLongitudeRef= $exif['GPS']['GPSLongitudeRef'];
        $GPSLongitude   = $exif['GPS']['GPSLongitude'];
        
        $lat_degrees = count($GPSLatitude) > 0 ? gps2Num($GPSLatitude[0]) : 0;
        $lat_minutes = count($GPSLatitude) > 1 ? gps2Num($GPSLatitude[1]) : 0;
        $lat_seconds = count($GPSLatitude) > 2 ? gps2Num($GPSLatitude[2]) : 0;
        
        $lon_degrees = count($GPSLongitude) > 0 ? gps2Num($GPSLongitude[0]) : 0;
        $lon_minutes = count($GPSLongitude) > 1 ? gps2Num($GPSLongitude[1]) : 0;
        $lon_seconds = count($GPSLongitude) > 2 ? gps2Num($GPSLongitude[2]) : 0;
        
        $lat_direction = ($GPSLatitudeRef == 'W' or $GPSLatitudeRef == 'S') ? -1 : 1;
        $lon_direction = ($GPSLongitudeRef == 'W' or $GPSLongitudeRef == 'S') ? -1 : 1;
        
        $latitude = $lat_direction * ($lat_degrees + ($lat_minutes / 60) + ($lat_seconds / (60*60)));
        $longitude = $lon_direction * ($lon_degrees + ($lon_minutes / 60) + ($lon_seconds / (60*60)));

        return array('latitude'=>$latitude, 'longitude'=>$longitude);
    }else{
        return false;
    }
}


$imgURL = 'prop_img/20200419_105335.jpg';
$imgLocation = get_image_location($imgURL);

$imgLat = $imgLocation["latitude"];
$imgLng = $imgLocation["longitude"];

echo  'Latittude : ' . $imgLat;
echo '<br>longitude : ' . $imgLng . '<br><br>';

?>

<img src="<?php echo $imgURL; ?>" style="width: 150px;"><br><br>

<div id="map"></div>
<style type="text/css">
  #map { width: 500px; height: 500px; }
</style>



 <script>

      function initMap() {
        var myLatLng = {lat: <?php echo $imgLat; ?>, lng: <?php echo $imgLng; ?>};

        var map = new google.maps.Map(document.getElementById('map'), {
          zoom: 18,
          center: myLatLng
        });

        var marker = new google.maps.Marker({
          position: myLatLng,
          map: map,
          title: 'Hello World!'
        });
      }
    </script>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script src="https://maps.googleapis.com/maps/api/js?key=<?php echo $gmkey; ?>&callback=initMap" async defer></script>

</body>
</html>

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Sunday, April 19, 2020

Extract Geocoding Latitude Longitude from Image / Photo using PHP with Google MAP API [SOLVED]

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